CBSE BOARD XII, asked by aayushpathak20pe0um2, 9 months ago

Q)Three particles A, B and C are situated at the verticles of an equilateral triangle of side L. Each of the particle starts moving with a constant velocity v such that A is always directed towards B, B towards C and C towards A. Find the time when they meet.

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Answered by krishna472083
1

Answer:

hree particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t=0. Each of the particles moves with constant speed v. A always has its velocity along AB, B along BC and C along CA. ... Thus the separation of partivles at (A) and (B) dereases with the speed=v+v/2=3v/2.

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