Question

Q = Three unbaised coins are tossed together.
Find the probability of getting
(al two heads
(b) at least two heads
(c).at most one head.​

Answer 1

Answer:

A.3/8

B.4/8

C.4/8

Step-by-step explanation:

s = {hhh,hht,hth,thh,ttt,tth,tht,htt}

n(s)=8

a) let A be the probability of getting two heads

A={hht,hth,thh}

n(A)=3

P(A)=3/8

b) let B be the probability of getting atleast two heads

B={hhh,hht,hth,thh}

n(B)=4

P(B)=4/8

c)

let c be the event of getting atmost one head

c={ttt,tth,tht,htt}

n(c)=4

P(C)=4/8

HOPE YOU UNDERSTAND