Question

Q- To make a 1L solution of 0.1N MgCl2 from a 10N stock solution of MgCl2, the volume of H20 and
10N MgCl, that is needed to be mixed will be:
1. 800ml H20 + 200ml MgCl2
2. 999ml H20 + 1ml MgCl2
3. 900ml H20 + 100ml MgCl2
4. 990ml H20 + 10ml MgCl2
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Answer 1

Explanation:

900ml H20 + 100ml MgCI2