Question

Q].train moves from rest to a speed of 25 m/s in 30 seconds. What is the magnitude of its acceleration?​

Answer 1

Answer:

Given:-

Initial velocity ,u = 0m/s

Final velocity ,v = 25m/s

Time taken ,t = 30

To Find:-

Magnitude of Acceleration ,a

Solution:-

we have to calculate the magnitude of acceleration.

As we know that acceleration is defined as the rate of change in velocity .

a = v-u/t

where

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

:\implies:⟹ a = 25-0/30

:\implies:⟹ a = 25/30

:\implies:⟹ a = 0.833 m/s²

Hence, the acceleration of the train is 0.833 m/s².

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Answer 2

★ Given :

• ➝ Initial velocity of train (u) = 0
• ➝ Final velocity of train (v) = 25m/s
• ➝ Time taken by train (T) = 30sec

★ Need to Find :

• ➲ Acceleration of the train ?

★ Formula Used Here :

• ➲ v = u + at

✰ Where :

• ↠ v = Final velocity
• ↠ u = Initial velocity
• ↠ a = acceleration
• ↠ t = Time taken

✯ Understanding the concept :

• ➥ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of train !

✯ Putting value in formula :

• ↠ v = u + at
• ↠25m/s = 0 + a × 30s
• ↠ 25 = 0 + 30a
• ↠ 25 = 30a
• ↠ a = 0.83 m/s²

✰ Therefore :

• ➦ Acceleration of train is a = 0.83m/s²

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