Question

Q].train moves from rest to a speed of 25 m/s in 30 seconds. What is the magnitude of its acceleration?​

Answer 1

★ Given :

• ➝ Initial velocity of train (u) = 0
• ➝ Final velocity of train (v) = 25m/s
• ➝ Time taken by train (T) = 30sec

★ Need to Find :

• ➲ Acceleration of the train ?

★ Formula Used Here :

• ➲ v = u + at

✰ Where :

• ⟶ v = Final velocity
• ⟶ u = Initial velocity
• ⟶ a = acceleration
• ⟶ t = Time taken

✯ Understanding the concept :

• ➥ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of train !

✯ Putting value in formula :

• ⟶ v = u + at
• ⟶ 25m/s = 0 + a × 30s
• ⟶ 25 = 0 + 30a
• ⟶ 25 = 30a
• ⟶ a = 0.83 m/s²

✰ Therefore :

• ➦ Acceleration of train is a = 0.83m/s²

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Answer 2

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Given:

• Initial velocity (u) = 0
• Final velocity (v) = 25m/s
• Time taken (t) = 30sec

Using 1st equation of motion :

v = u + at

Now, putting values in it, accordingly.

$\rm 25 = 0 +( a \times 30)$

$\rm 25 - 0 = a \times 30$

$\rm 25 = a \times 30$

$\rm \frac{25}{30} = a$

$\rm 0.83 = a$

Therefore, acceleration attained by the train is 0.83m/s²

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