Question

Q].train moves from rest to a speed of 60 m/s in 30 seconds. What is the magnitude of its acceleration?​

Answer 1

★ Given :

• ➝ Initial velocity of train (u) = 0
• ➝ Final velocity of train (v) = 60m/s
• ➝ Time taken by train (T) = 30sec

★ Need to Find :

• ➲ Acceleration of the train ?

★ Formula Used Here :

• ➲ v = u + at

✰ Where :

⟶ v = Final velocity

⟶ u = Initial velocity

⟶ a = acceleration

⟶ t = Time taken

✯ Understanding the concept :

• ➥ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of train !

✯ Putting value in formula :

⟶ v = u + at

⟶ 60m/s = 0 + a × 30s

⟶ 60 = 0 + 30a

⟶ 60 = 30a

⟶ a = 2 m/s²

✰ Therefore :

• ➦ Acceleration of train is a = 2m/s²

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Answer 2

Answer:

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