Question

Q●Triangle ABC is a right angled triangle at A and AD is perpendicular to BC . Also,angle B = 55° find the following angle.
a.angle BAD
b.angle CAD
c.angle ACB



with full solving process and explanation. ​

Answer 1

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A.) For angle BAD :-

Since, AD is prependicular to BC

∴ Angle ADB = 90°

Now in ∆ ADB,

Angle A + Angle B + Angle D = 180° (Angle sum property of triangle)

=> Angle A + 55° + 90° = 180°

=> Angle A = 180° - 145°

=> Angle A = 35°

=> Angle BAD = 35°

B.) For angle CAD :-

Now,

Angle CAB = Angle CAD + Angle BAD

=> 90° = Angle CAD + 35° (Angle CAB = 90°, given)

=> 90° - 35° = Angle CAD

=> Angle CAD = 55°

C.) For Angle ACB :-

Now, in ∆ ABC

Angle B = 55° (Given)

Angle A = 90° (Given)

Let angle C = 'x'

A.T.Q.

Angle B + Angle A + Angle C = 180° (Angle sum property of triangle)

=> 55° + 90° + x = 180°

=> 145° + x = 180°

=> x = 180° - 145°

=> x = 35°

=> Angle ACB = 35°

Answers :-

• Answers :- Angle BAD = 35°
• Answers :- Angle BAD = 35° Angle CAD = 55°
• Answers :- Angle BAD = 35° Angle CAD = 55° Angle ACB = 35°