Math, asked by sanghmitra1301, 4 months ago

Q. Two digit no. four times the sum of its digit and twice
and the product of its digit. Find the no.​

Answers

Answered by shubhamkh9560
0

Answer:

Your answer

Step-by-step explanation:

Let the digit in the ones place be x and tens place be y

Hence the two digit number =10y+x

Given that the two digit number =4 times sum of its digits

According to the question,

⇒ 10y+x=4(x+y)

⇒ 10y+x=4x+4y

⇒ 3x−6y=0

⇒ x=2y

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Answered by singhanurudh06
0

Answer:

36

Step-by-step explanation:

let the required no. be 10x+y -----(1)

Given: 10x+y = 4(x+y) -----(2)

and 10x+y = 2xy -----(3)

On solving equations (1) and (2) we get y=2x and x=3

Put the value of x in y and you will get y=6

Putting the values of x and y in (1) we get 36 i.e., the required number.

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