Q). Two identical parallel plate capacitor C1 and C2 have capacitance C each . The space between their plates is now filled with dielectric as shown. If the two capacitors still have equal capacitance ,obtain the ratio between dielectric constant K , K1 and K2.
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Let Area of each plate = A
Capacitance,
C=ε0A / (d−t)+t/K
C1=ε0A / (d−t)+t/K1
C2=ε0A /(d−t)K1
it is not given that inhow much spce the dielectric is filled.
ε0A /(d−t)+t/K1=ε0A / (d−t)+t / K2
(d−t) + t / K2= (d−t) + t / K2
⇒K1=K2
============
@GautavSaxena01
Capacitance,
C=ε0A / (d−t)+t/K
C1=ε0A / (d−t)+t/K1
C2=ε0A /(d−t)K1
it is not given that inhow much spce the dielectric is filled.
ε0A /(d−t)+t/K1=ε0A / (d−t)+t / K2
(d−t) + t / K2= (d−t) + t / K2
⇒K1=K2
============
@GautavSaxena01
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