Question

Q. two numbers are in the ratio 5 : 3 . if they differ by 18 , what are the numbers?

a) 45,27
b) 35,17
c) 25,7
d) 55,37 ​

Answer 1

$\sf\red{\underline{\underline{Answer:}}}$

$\sf{Numbers \ are \ 45 \ and \ 27.}$

$\sf\orange{Given:}$

$\sf{\implies{Two \ numbers \ are \ in \ the \ ratio \ of \ 5:3}}$

$\sf{\implies{Numbers \ differ \ by \ 18}}$

$\sf\pink{To \ find:}$

$\sf{The \ numbers}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Let \ the \ common \ multiple \ be \ x.}$

$\sf{\therefore{Numbers \ are \ 5x \ and \ 3x}}$

$\sf{According \ to \ the \ given \ condition.}$

$\sf{5x-3x=18}$

$\sf{\therefore{2x=18}}$

$\sf{\therefore{x=\frac{18}{2}}}$

$\boxed{\sf{\therefore{x=9}}}$

$\sf{Numbers=5(9) \ and \ 3(9)}$

$\sf{=45 \ and \ 27}$

$\sf\purple{\tt{\therefore{Numbers \ are \ 45 \ and \ 27.}}}$

Answer 2

Answer:

Given:

ratio of number = 5:3

assume the numbers as 5x and 3x.

difference = 18

5x-3x = 18

2x= 18

x= 18/2

x= 9

by putting the value of x.

5x = 5×9 = 45

3x= 3×9 = 27

hence ,the answer is option (a).