Question

Q. Two point masses each of mass 5 kg are situated at the ends of a massless thin rod of length 1-0 m. Find the moment of inertia of the system when axis of rotation : (i) passes through the centre of mass and is perpendicular to the length of rod. (ii) passes through a particle and is perpendicular to the length of a rod. con




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Answer 1

Answer:

Given,

Both objects have mass =M

The separation between them =L

Both objects has equal mass, canter of mass will be at the axis.

 

Distance of object from center of mass d=2L

Moment of Inertia = Mass X (Distance from axis)2

Total moment of Inertia = Moment of Inertia of object 1 + Moment of Inertia of object 1

I=Md2+Md2

I=M(2L)2+M(2L)2

I=2ML2

Moment of Inertia of system I=2ML2

Explanation:

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Answer 2

Answer:

no

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