Question

Q=Two trees,A and B are on the same side of a river .From a point C in the river the distance of the trees A and B is 250 m and 300 m,respectively .If the angle C is 45o ,find the distance b/w the trees (use root 2 =1.44). PLS CALCULATE AND SHOW

Answer 1

Simple application of Pythagoras theorem.

see diagram.

Draw a perpendicular AD from A on to BC.  In the right angle triangle ΔACD, 
∠ACD = 45°     ∠D=90°  So  ∠CAD = 45°
Hence,  AD= CD. 
As   AC² = AD² + CD²,      
     So  AD = CD = AC/√2 = 250/√2 = 125√2 cm = 180 m

So BD = 300 - 180 = 120 m

In the right angle ΔADB,   AB² = AD² + DB²
   AB² = 180² + 120² 
       AB  = 60 √13 m

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