Question

Q) Two vectors of magnitude 2N and 4N are acting at an angle 60⁰ , Find :-
1) Magnitude of resultant.
2) Angle between resultant and 4N .
3) Angle between resultant and 2N .
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Answer 1

Answer:

1) magnitude of resultant=$\sqrt{2^{2}+4^{2}+2*4*cos60\\}$=$\sqrt{24}$

2) angle between resultant and 4N=tanα=2sin60/(4+2cos60)=$\sqrt{3}$/5

3) angle between resultant and 2N=tanα=4sin60/(2+4cos60)=2$\sqrt{3}$/4=$\sqrt{3}$/2

Answer 2

$\huge\underline\bold\red{ANSWER}$

The resultant of two force is given by F =

$\sqrt{a2 + b2 + 2ab} \cos(θ)$

$2×102+2×100cos600 =103N. \sqrt{?}$