Question

Q:-Use suitable identities to find the following products : (I) (X+8) (X - 10) (II) (X+4) (X+10)
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Answer 1

Step-by-step explanation:

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Q:-Use suitable identities to find the following products : (I) (X+8) (X - 10) (II) (X+4) (X+10)

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solving (I)

$⟹(x + 8)(x - 10)$

Here this identify is used:-

$⟹(x + a)(x - b) = {x}^{2} + (a + b)x + ab$

$⟹(x + 8)(x - 10) = {x}^{2} + (8 + ( - 10))x + - 8 \times 10$

$⟹ {x}^{2} - 2x - 80 = 0$

solving (ii)

$⟹(x + 4)(x + 10)$

$⟹(x + 4) (x - 10) = {x}^{2} + (4 + ( - 10))x + 4 \times - 10$

$⟹ {x}^{2} - 6x - 40 = 0$

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

Solving (1) :

⟹ (x + 8)(x - 10)

⟹(x+8)(x−10)

→ Here this identify is used:-

⟹(x + a)(x - b) = {x}^{2} + (a + b)x + ab

⟹(x+a)(x−b)=x

2

+(a+b)x+ab

⟹(x + 8)(x - 10) = {x}^{2} + (8 + ( - 10))x + - 8 \times 10⟹(x+8)(x−10)=x

2

+(8+(−10))x+−8×10

⟹ {x}^{2} - 2x - 80 = 0⟹x

2

−2x−80=0

solving (ii)

⟹(x + 4)(x + 10)⟹(x+4)(x+10)

⟹(x + 4) (x - 10) = {x}^{2} + (4 + ( - 10))x + 4 \times - 10⟹(x+4)(x−10)=x

2

+(4+(−10))x+4×−10

⟹ {x}^{2} - 6x - 40 = 0⟹x

2

−6x−40=0