Q . What is the area between parabola Y²= 16X and line y = X – 5.
Answers
Answer:
Y² = 16X
Y = √16X
Y = 4X
y = X – 5
4X = X –5
4X – X = –5
3X = – 5
X = – 5/3
: (2) 4
Intersection points of both the curves are (0,0) and (16m2,16m). Therefore, required area =∫16/m20(√16x−mx)dx=23⇒[4⋅23x3/2−mx22]16/m20=23=83(16m2)3/2−m2(16m2)2=23⇒83⋅64m3−16×162m3=23⇒1m3[5123−2562]=23⇒m3=1283×32=64∴m=4 Intersection points of both the curves are (0,0) and (16m2,16m). Therefore, required area =∫016/m2(16x−mx)dx=23⇒[4⋅23x3/2−mx22]016/m2=23=83(16m2)3/2−m2(16m2)2=23⇒83⋅64m3−16×162m3=23⇒1m3[5123−2562]=23⇒m3=1283×32=64∴m=4
Related LinksArea enclosed by the curve π[4(x - √2)2 + y2] = 8 isArea of the greatest rectangle that can be inscribed in the ellipse x2 / a2 + y2 / b2 = 1 isArrange the following amino acids in order of their PKa order.Arrange the following in order of Kb valueArrange the following solutions in the decreasing order of pOHAs shown in the figure, a block of mass √3 kg is kept on a horizontal rough surface of coefficient of friction 1/3√3.Assertion : The resolving power of a telescope is more if the diameter of the objective lens is more. Reason : Objective lenses of large diameter collectd more light.Assertion Power developed in circular motion is always zero. Reason Work done in case of circular motion is