Math, asked by Nishi5533, 10 months ago

Q.
What is the area of the triangle ABC with A (1, -
4),B(2, -1) and C (0, -1)
A)
2
B)
3
C)
4
D)
None of these

Answers

Answered by Aloi99

Given:-

๛A=(1,-4)→(x1,y1)

๛B=(2,-1)→(x2,y2)

๛C=(0,-1)→(x3,y3)

$\rule{200}{1}$

To Find:-

✪The Area of the ∆le[Triangle]?

$\rule{200}{1}$

AnsWer:-

☞3 sq.units or Option B)

$\rule{200}{1}$

Explanation:–

✪Using Area of Triangle formula✪

➜½×[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

♦Putting the Value♦

↝½[1(-1-(-1)+2(-1-(-4)+0(-4-(-1)]

↝½[1(-1+1)+2(-1+4)+0(-4+1)]

↝½[0+6+0]

↝½×6

↝ $\frac{\cancel{6}}{\cancel{2}}$

↝3sq.units

RvChaudharY50: Cool.

BrainIyMSDhoni: Great :)

Answered by Anonymous

Given:

Coordinates of ∆ABC are:

◾️A(1,-4)

◾️B(2,-1)

◾️C(0,-1)

To Find :

Area of ∆ABC

Formula Used:

$\sf \: Area \: of \: triangle = \frac{1}{2}\times[ {x_{1}(y_{2} - y_{3}) + x_{2}(y_{3} - y_{1}) + x_{3}(y_{1} - y_{2})}$ ]

Solution:

Let's consider the coordinates as :

A(1,-4) as (x1,y1)

B(2,-1) as (x2,y2)

C(0,-1) as (x3,y3)

Calculation:

$\rightarrow \: \sf \: Area = \frac{1}{2} \times[1( - 1 + 1) + 2( - 1 + 4) + 0 ]\\ \\ \rightarrow \sf \: Area = \frac{1}{\cancel2} \times \cancel6 \\ \\ \rightarrow \sf \: Area = 3 \: square \: units$

Therefore, the area of ∆ABC is 3 square units. So, correct option is (B).

RvChaudharY50: Nice.

BrainIyMSDhoni: Great :)

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Q.What is the area of the triangle ABC with A (1, -4),B(2, -1) and C (0, -1)A)2B)3C)4D)None of these​

Answers

Given:-

To Find:-

AnsWer:-

☞3 sq.units or Option B)

Explanation:–

✪Using Area of Triangle formula✪

♦Putting the Value♦

Given:

To Find :

Formula Used:

Solution:

Calculation:

Q.
What is the area of the triangle ABC with A (1, -
4),B(2, -1) and C (0, -1)
A)
2
B)
3
C)
4
D)
None of these