Q)What is the maximum horizontal distance that a ball thrown with a speed of 60 m/s can go without hitting the roof of a long hall 30m high? (Take g=10m/s)
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Answer:
ANSWER
H
max
=
g
μ
2
sin
2
θ
=25m
=
9.8
(40)
2
×sin
2
θ
=25m
sin
2
θ =0.153125
θ=23
0
Now, T
g
2μsinθ
=
9.8
2×40×0.4
=3.19sec
Now, x = μcosθ×T
=40x cos(23
0
) x 3.19
x= 117.62 m
Therefore , maximum horizontal distance is 117.62 metres.
Explanation:
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