Question

Q:What is the molarity of 6,3 g of oxalic acid in 250 ml solution.​

Answer 1

Answer:

0.25M

Explanation:

$\bold{Fomula \: used :\: Molarity = \frac{(Moles \: of \: oxalic \: acid)}{(Total \: volume \: of \: oxalic \: acid )in \: lt.}. } \\ \\ \bold{And \: Moles \: of \: oxalic \: acid = \frac{Given \: mass}{Molar \: mass}.} \\ \\ \bold{ \therefore{Moles \: = \: \frac{63g}{90.03g} = 0.69 \: mols. }} \\ \\ \bold{ \therefore{Molarity = \frac{0.63 \times 100}{250} = 0.25 \:M }.}$