Question

Q) What is the nature of the
roots of the quadratic equation
4x2 - 8x +9 = 0?
​

Answer 1

Answer:

Imaginary Roots

Step-by-step explanation:

4x^2 -8x + 9 = 0

a= 4 , b= -8 c=9

Discriminant = b^2 - 4ac

(-8)^2 - 4×4×9

64 - 144

= - 80

The roots are imaginary because roots cannot be negative .

Hope it helps..

Answer 2

Answer:

NO REAL ROOTS.

Step-by-step explanation:

4x² - 8x + 9 = 0

quadraric equation is in the form of

ax²+bx+c = 0

To find the nature of roots, we have to find

D = b² - 4ac

D = (8)² - 4(4)(9)

= 64 - 144

= - 80

D < 0 ; it has no real roots.

NATURE OF ROOTS :

If D < 0 ; no real roots.

If D = 0 ; real and equal roots.

If D > 0 ; real and unequal roots.