Question

Q. what mass of HCl is required to consume 50 g of CaCO3 completely
option :- 73g, 36.5g, 7.3g, 3.65g​

Answer 1

Explanation:

Correct option is

A

36.5 g

Chemical reaction involved is:

CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

Molar mass of HCl=1+35.5=36.5 g

According to the balanced reaction 100 g of CaCO

3

requires 2×36.5=73 g of HCl

∴50 g CaCO

3

requires:

100

73

×50=36.5 g HCl

Hence, option A is correct.

verified_toppr

Answer verified by

veeresh gouda

Answer 2

Answer:

36.5 g

Explanation:

Chemical reaction involved is:

CaCO3+2HCl→CaCl2+H2O+CO2

Molar mass of CaCO3=

$40 + 12 + 16 \times 3 = 100gm$

Molar mass of HCl=

$1 + 35.5 = 36.5g$