Q. what volume of 95% by weight sulphuric acid (specific gravity is 1.85 g oer ml)and what mass of water must be taken to prepare 100 ml 15% by weight solution of sulphuric acid(density is 1.1 g per ml)
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● Answer -
9.4 ml 95% H2SO4 in 90.6 ml water
● Explaination -
Total mass of solution
= density × volume
= 1.1 × 100
= 110 g
Mass of 15% H2SO4 in solution
= 110 × 15/100
= 16.5 g
Mass of water in solution
= 110 - 16.5
= 93.5 g
Mass of 95% H2SO4 required
= 100 × 16.5 / 95
= 17.37 g
Volume of 95% H2SO4 required
= 17.37 / 1.85
= 9.4 cm^3
= 9.4 ml
Volume of water required
= 100 - 9.4
= 90.6 ml
Therefore, 9.4 ml of 95% H2SO4 should be added in 90.6 ml water.
Hope this helps you...
● Answer -
9.4 ml 95% H2SO4 in 90.6 ml water
● Explaination -
Total mass of solution
= density × volume
= 1.1 × 100
= 110 g
Mass of 15% H2SO4 in solution
= 110 × 15/100
= 16.5 g
Mass of water in solution
= 110 - 16.5
= 93.5 g
Mass of 95% H2SO4 required
= 100 × 16.5 / 95
= 17.37 g
Volume of 95% H2SO4 required
= 17.37 / 1.85
= 9.4 cm^3
= 9.4 ml
Volume of water required
= 100 - 9.4
= 90.6 ml
Therefore, 9.4 ml of 95% H2SO4 should be added in 90.6 ml water.
Hope this helps you...
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