Question

Q. What would be the number of amino acids coded by given mRNA nucleotide sequence?
AUGCUGAGGUAAUGA
(Correct answer is 3)
#No Spamming please
#Do not post just writting 3 in the answer I need an explanation​

Answer 1

Answer:

3

Explanation:

3 nucleotide bases forms one codon and each codon codes for an amino acid

if you divided the nucleotide bases given in the mRNA above into codons. They will form

AUG CUG AGG UAA UGA

AUG- codes for methionine

CUG- codes for Leucine

AGG - codes Leucine

UAA - Stop codon

UGA - Stop codon.

the Stop codons don't code for any amino acids. They help in the termination of translation process. Therefore only 3 codons in the given mRna codes for amino acids.