Q. What would be the number of amino acids coded by given mRNA nucleotide sequence?
AUGCUGAGGUAAUGA
(Correct answer is 3)
#No Spamming please
#Do not post just writting 3 in the answer I need an explanation
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Answer:
3
Explanation:
3 nucleotide bases forms one codon and each codon codes for an amino acid
if you divided the nucleotide bases given in the mRNA above into codons. They will form
AUG CUG AGG UAA UGA
AUG- codes for methionine
CUG- codes for Leucine
AGG - codes Leucine
UAA - Stop codon
UGA - Stop codon.
the Stop codons don't code for any amino acids. They help in the termination of translation process. Therefore only 3 codons in the given mRna codes for amino acids.
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