Q.When a conductor of cross sectional area of 5.0x10-6 me carries a current of 6.0A, the drift velocity of conduction electrons is 1.2x10-4 ms-. What is the number density (number per unit volume) of the conduction electrons?
Please answer clearly with solution. it's Entry Test MCQ.
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Q. a 10 nano farad (10 x 10-9 F) parallel plate capacitor holds a charge of magnitude 50 micro C on each plate. if the plates are separated by a distance of 0.885 mm, what is the area of the plate ?
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capacitance is =al to epsilin not A /d
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Answered by
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The formula for electric current relating the drift velocity is:
I = neAV
Where,
I = Electric current
n = Number of charges per unit volume
e = Electron charge
A = Cross sectional area
V = Drift speed
Solving for 'n'
n = I/eAV
Here
I = 6.0 Amp
e = 1.6 * 10^-19 C
A = 5.0 * 10^-4 m^2
V = 1.2 * 10^-4 m/s
Put all these values in above equation and do the calculations:
n = (6.0)/ (1.6 * 10^-19) (5.0 * 10^-4) (1.2 * 10^-4)
n = 6.3 × 10^28 m^-3 Answer
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