Question

Q. where should the tank be punctered so that
water coming out has
has maximum horizontal
range?
v= √2gch-y
(class 11)​

Answer 1

Answer:

I am in class 6 sorry....

Answer 2

Answer:y = h/2

Explanation:

Range = 2√[(h-y)y]

And Rmax = h

So, h = 2√[(h-y)y]

h² = 4(hy-y²)

4y² -4hy +h² = 0

Solving this we get

y= h/2