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Q.Write some Question of Newton second law...

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Answered by AnswerStation
13
HEY MATE,
Here is your answer

Some questions related to Newton's {2}^{nd} Law of motion are :


1) An object of 50kg gets speed of 10m/s in 5 seconds from zero velocity. Calculate required force applied by engine of car.

Answer - F = 100N


2) A car having mass of 1500 kg achieves velocity of 5 m/s in 10 seconds. Calculate the required force to attain required speed by car.

Answer - 750N


3) An object gets 20 seconds to increase speed from 10m/s to 50m/s. If mass of object is 1000 kg, what force will be required to do so?

Answer - 800N


Hope this helps!!!!

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Answered by nikolatesla2
3
A metre scale is moving with uniform velocity. This implies(a) the force acting on the scale is zero, but a torque about the centre of mass can act on the scale.(b) the force acting on the scale is zero and the torque acting about centre of mass of the scale is also zero.(c) the total force acting on it need not be zero but the torque on it is zero.(d) neither the force nor the torque need to be zero.
In the previous problem (5.3), the magnitude of the momentum transferred during the hit is(a) Zero(b) 0.75 kg m s–1(c) 1.5 kg m s–1(d) 14 kg m s–1Conservation of momentum in a collision between particles can be understood from(a) conservation of energy.(b) Newton’s first law only.(c) Newton’s second law only.(d) both Newton’s second and third law.A hockey player is moving northward and suddenly turns westward with the same speed to avoid an opponent. The force that acts on the player is(a) frictional force along westward.(b) muscle force along southward.(c) frictional force along south-west.(d) muscle force along south-west.A body of mass 2kg travels according to the law x(t ) = pt + qt2 + rt3 where p = 3 ms-1, q = 4 ms-2 and r = 5 ms-3. The force acting on the body at t = 2 seconds is(a) 136 N(b) 134 N(c) 158 N(d) 68 N(a) never(b) 10 s(c) 2 s(d) 15 s


Multiple Choice Questions (MCQ II)

The motion of a particle of mass m is given by x = 0 for t < 0 s, x( t ) = A sin 4p t for 0 < t <(1/4) s (A > o), and x = 0 for t >(1/4) s. Which of the following statements is true?(a) The force at t = (1/8) s on the particle is –16π2 A m.(b) The particle is acted upon by on impulse of magnitude 4π2 A m at t = 0 s and t = (1/4) s.(c) The particle is not acted upon by any force.(d) The particle is not acted upon by a constant force.(e) There is no impulse acting on the particle.In Fig. 5.1, the co-efficient of friction between the floor and the body B is 0.1. The co-efficient of friction between the bodies B and A is 0.2. A force F is applied as shown on B. The mass of A is m/2 and of B is m. Which of the following statements are true?
(a) The bodies will move together if F = 0.25 mg.(b) The body A will slip with respect to B if F = 0.5 mg.(c) The bodies will move together if F = 0.5 mg.(d) The bodies will be at rest if F = 0.1 mg.(e) The maximum value of F for which the two bodies will move together is 0.45 mg.Mass m1 moves on a slope making an angle θ with the horizontal and is attached to mass m2 by a string passing over a frictionless pulley as shown in Fig. 5.2. The co-efficient of friction between m1 and the sloping surface is μ.

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