q(y) = 3y2 - 4y + V11 at y = 2.
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Answered by
1
Answer:
V=-4/11
Step-by-step explanation:
we know that the value of y=2
put the value of y in equation.
q(2)=3×2×2-4×2+V11
q(2)=12-8+V11
q(2)=4+V11
q(2)=V11+4
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