Question

ᴩʟᴇᴀꜱᴇ ᴀɴꜱᴡᴇʀ ᴛʜᴇꜱᴇ qᴜᴇꜱᴛɪᴏɴꜱ ꜰᴏʀ ᴍᴇ ɢᴜyꜱ : (ᴡɪᴛʜ ꜱᴛᴇᴩꜱ)
(i) 1 + xy + x + x²y
(ii) a³ - 9a² + a - 9
ᴄʟᴀꜱꜱ 8 : ꜰᴀᴄᴛᴏʀɪꜱᴀᴛɪᴏɴ ᴏꜰ ᴀʟɢᴇʙʀᴀɪᴄ ᴇxᴩʀᴇꜱꜱɪᴏɴꜱ​​
urgent....

Answer 1

Step-by-step explanation:

i)

$1 + xy + x + {x}^{2} y$

=

$1 + x + xy + {x}^{2} y$

=

$(1 + x )+ xy(1 + x)$

=

$(1 + x)(1 + xy)$

ii)

${a}^{3} - 9 {a}^{2} + a - 9$

=

${a}^{2} (a - 9) + (a - 9)$

=

$( {a}^{2} + 1)(a - 9)$

Answer 2

Step-by-step explanation:

${a}^{3} - 9 {a}^{2} + a - 9$

$= {a}^{2} (a - 9) + 1( {a} - 9)$

$= (a - 9)( {a}^{2} + 1)$

$xy + 1 + {x}^{2}y + x$

$= 1(xy + 1) + x(xy + 1)$

$= (xy + 1)(x + 1)$

I hope it helps you. If you have any doubts, then don't hesitate to ask.