Math, asked by aarna27anand, 8 months ago

q(y) = root 11 - 4y + 3y power 3
y= 2

Answers

Answered by ritikamehta486
0

Answer:

If it is right please make it brainliest

Attachments:
Answered by ReginaGeorge
2

Answer:

decimal value k liye sqrt 11 ki value daal denge, aa jayega

Step-by-step explanation:

q(y) =  \sqrt{11}  - 4y + 3 {y}^{3} \: at \: y = 2  \\ q(2) =  \sqrt{11}  - 4(2) + 3 \times  {2}^{3}  \\  =  \sqrt{11 }  - 8 + 3 \times 8 \\   = \sqrt{11}  - 8 + 24 \\  =  \sqrt{11}  + 16

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