Question

Q. y = x^2 + 6x + 10; then minimum value of y is
(a) 1
(b) 2
(C) 3
(d) None of these​

Answer 1

Step-by-step explanation:

None of these....

if u differencate y then dy/dx= 2x+6

if 2x+6=0

x= - 3

here on second differencate gives 2 which is greater than 0

hence x= -3 gives minimum value....

so none of these ans..