Question

Q03: Find all the Zeroes of x3 + 6x2 + 11x + 6 if (x + 1) is a factor.​

Answer 1

Answer:

Step-by-step explanation:

Hope it helps

Please mark it brainliest

And follow me for more answers :)✌✌✌✌

Answer 2

Answer:

zeroes of x3 + 6x2 + 11x + 6 are

1. x= -2
2. x= -3
3. x=-1

Step-by-step explanation:

The quotient is the range of instances a department is finished fully, even as the the rest is the quantity left that does not absolutely pass into the divisor.

___________

X+1 √ x³-6x² +11x +6 \ x² +5x+6

X³- x²

__________

5x² + 11x

5x² + 5x

____________

6x + 6

6x + 6

___________

0

___________

Hence ,

Quotient : x² + 5x +6

Remainder: 0

now solving quotient:

$</p><p> x²+5x+6 \\ = x²+ 3x+2x +6 \\ = (x+3)(x-2)$

hence ,

zeroes of x3 + 6x2 + 11x + 6 are

1. x= -2
2. x= -3
3. x=-1

(#SPJ2)