Question

Q04 :/ Prove that root 6+root 5 is irrational.​

Answer 1

Answer:

√6 is rational but contradict the fact that √6 is irrational

Answer 2

Step-by-step explanation:

let us assume on the contrary that $\sqrt{6}$ +$\sqrt{5}$ is rational.

i.e,we can find co prime a and b (b $\neq$0) such that $\sqrt{6}$+$\sqrt{5}$ =a/b

that is $\sqrt{5}$ and$\sqrt{6}$ are rational

but this contradicts the fact that $\sqrt{5}$ and $\sqrt{6}$  are irrational

,and this has arisen due to our incorrect assumption

therefore $\sqrt{6}$ +$\sqrt{5}$  is irrational