Q1 = (1) (2)
Q2= (1) (2)
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we have to solve both the sums by using the identity (a2-b2) =(a+b)(a-b)
q1
1) 4p2-9=(2p-3) (2p+3)
2)4x2-169y2=(2x+13y)(2x-13y)
q2
1) 9x2y2-25=(3xy-25) (3xy+25)
2)16x2-1/144=(4x+1/12)(4x-1/12)
q1
1) 4p2-9=(2p-3) (2p+3)
2)4x2-169y2=(2x+13y)(2x-13y)
q2
1) 9x2y2-25=(3xy-25) (3xy+25)
2)16x2-1/144=(4x+1/12)(4x-1/12)
her783o:
bhai
Answered by
1
q1 4p²-9
(2p)²-(3)²
( 2p+3)(2p-3)
ii. 4x²-169y²
( 2x)²-(13)²
( 2x+13)(2x-13)
2 9x²y²-25
( 3xy)²-(5)²
( 3xy+5)(3xy-5)
please mark brainliest
2 ii) 16x²-1/144
(4x)²-(1/12)²
(4x+1/12)(4x-1/12)
(2p)²-(3)²
( 2p+3)(2p-3)
ii. 4x²-169y²
( 2x)²-(13)²
( 2x+13)(2x-13)
2 9x²y²-25
( 3xy)²-(5)²
( 3xy+5)(3xy-5)
please mark brainliest
2 ii) 16x²-1/144
(4x)²-(1/12)²
(4x+1/12)(4x-1/12)
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