Question

Q1.17. A man buys 18 comics and decides to divide them among his children in the
ratio of their ages. Their ages are 9 years, 6 years and 3 years. How many
comics will each child get?​

Answer 1

Explanation:

✬ Comics = 9 , 6 & 3 ✬

Step-by-step explanation:

Given:

Total number of comics he bought is 18.

Ages of his children are 9 years , 6 years and 3 years.

To Find:

How many comics each of them will get ?

Solution: Let x be the common in given ratios of children ages. Therefore

First child = 9x comics

Second child = 6x comics

Third child = 3x comics

∴ Total ratio = 9x + 6x + 3x

➙ Total ratio = 18x

Now , let's find the value of x.

⟹ Total ratio = Total comics

⟹ 18x = 18

⟹ x = 18/18

⟹ x = 1

So the number of comics each will get is

➯ First child = 9x = 9 × 1 = 9 comics

➯ Second child = 6x = 6 × 1 = 6 comics

➯ Third child = 3x = 3 × 1 = 3 comics

Hence, they will get 9 , 6 and 3 comics respectively.

Answer 2

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${\fcolorbox{pink}{white}{\pink{Comics = 9,6 and \: 3}}}$

Given:

Total number of comics he bought is 18.

Ages of his children are 9 years, 6

years and 3 years.

To Find:

How many comics each of them will get?

Solution:

Let x be the common in given ratios of children ages. Therefore

First child I = 9comics

Second hiId = 6xcomics

• Third child = 3x comics

.: total ratio = 9x + 6x + 3x

→ Total ratio = 18x

Now, let's find the value of x.

Total ratio = Total comics

18x = 18

x = 18/18

X = 1

So the number of comics each will get is

First child = 9x = 9 × 1 = 9 comics

Second child = 6x = 6 × 1 = 6 comics

➡ Third child = 3x = 3 × 1 = 3 comics

Hence, they will get 9, 6 and 3 comics respectively.

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