Question

Q1- {(3t-2)÷by 4}-(2t+1)= 2÷by 3-t​

Answer 1

Answer:

$\frac{(3t - 2)}{4} - (2t + 1) = \frac{2}{3 - t} \\ \frac{(3t - 2) - (8t + 4)}{4} = \frac{2}{3 - t} \\ \frac{3t - 2 - 8t - 4}{4} = \frac{2}{3 - t} \\ \frac{ - 5t - 6}{4} = \frac{2}{3 - t} \\ ( - 5t - 6)(3 - t) = 8 \\ - 15t + 5 {t}^{2} - 18 + 6t = 8 \\ 5 {t}^{2} - 9t = 26 \\ 5 {t}^{2} - 9t - 26 = 0$