Q1.4x + y=35,x + 4y=20 equation.
Answers
Explanation:
We have given two Equations 4x+y= 35 & x+4y= 20.We can solve it in various ways here we solve it through elimination method and substitution method.
By elimination method
➙4x+y= 35------(×1)
➙x+4y=20-------(×4)
New Equation obtained
➙4x+y=35
➙4x+16y=80
➙(-)(-)\:(-)(−)(−)(−)
___________
-15y= -45
15y=45
y= 45÷15=3
y=3
Put y's value into this equation
➙4x+y=35
➙4x+3=35
➙4x=35-3=32
➙4x=32
➙x= 32÷4=8
➙x=8
Hence, x = 8 & y= 3
Check:
➙4x+y=35
Taking LHS
➙4(8)+3
➙32+3=35
Since,LHS = RHS(verified)
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By substitution method
➙4x+y=35
x= (35-y)÷4------(1)
➙x+4y=20
From equation 1
➙35-y/4+4y=20
➙35-y+16y/4=20
➙35+15y= 80[20×4]
➙15y= 80-35
➙15y=45
➙y= 45÷15
➙y=3
Put y's value into equation 1
➙x= 35-y÷4
➙x= 35-3/4
➙x= 32/4
➙x=8
Answer:
Answer in the above attachment
