Q1. ਦੋਘਾਤੀ ਸਮੀਕਰਨ 5x? -4x +5=0 ਦੇ ਮੁਲਾਂ
et y last 3: The roots of quadratic
equation 5x2 - 4x +5=0 are: fara
ਸਸੀ 5x4 -4x +5=0 * ਸੈਂ: *
ਉ) ਵਾਸਤਵਿਕ ਅਤੇ ਸਮਾਨ Real and Equal
वास्तविक और समान
ਅ) ਵਾਸਤਵਿਕ ਅਤੇ ਅਸਮਾਨ Real and
unequal ਗਰਿਲ ਸੀ ਜਦ
ਬ) ਵਾਸਤਵਿਕ ਨਹੀਂ Not realਗਰਿਕ ਸਵੀਂ
ਸ) ਇਹਨਾਂ ਵਿੱਚੋ ਕੋਈ ਨਹੀਂ None of these
इनमें से कोई नहीं।
Answers
Step-by-step explanation:
TS
MCQ QUESTIONS
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RD Sharma Solutions , RS Aggarwal Solutions and NCERT Solutions
RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3D
July 10, 2018 by Prasanna Leave a Comment
RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3D
These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3D.
Other Exercises
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3A
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3B
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3C
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3D
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3E
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3F
Question 5.
Solution:
Using distributive law of multiplication over addition or subtraction,
(i) 740 x 105
= 740 x (100 + 5)
= 740 x 100 + 740 x 5
= 74000 + 3700
= 77700
(ii) 245 x 1008
= 245 x (1000 + 8)
= 245 x 1000 + 245 x 8
= 245000 + 1960
= 246960
(iii) 947 x 96
= 947 x (100 – 4)
= 947 x 100 – 947 x 4
= 94700 – 3788
= 90912
(iv) 996 x 367
= 367 x (1000 – 4)
=
(ii) 847 x 99 = 84 x (100 – 1)
= 847 x 100 – 847 x 1
= 84700 – 847
= 83853
(iii) 2437 x 999 = 2437 x (1000 – 1)
= 2437 x 1000 – 2437 x 1
= 2437000 – 2437
= 2434563
Question 7.
Solution:
RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3D 7.1
Question 8.
Solution:jjjjjjjTS
MCQ QUESTIONS
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RD Sharma Solutions , RS Aggarwal Solutions and NCERT Solutions
RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3D
July 10, 2018 by Prasanna Leave a Comment
RS Aggarwal Class 6 Solutions Chapter 3 Whole Numbers Ex 3D
These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3D.
Other Exercises
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3A
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3B
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3C
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3D
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3E
RS Aggarwal Solutions Class 6 Chapter 3 Whole Numbers Ex 3F
Question 1.
Solution:
(i) 246 x 1 = 246
(By multiplicative property of 1)
(ii) 1369 x 0 = 0
(By multiplicative property of 0)
(iii) 593 x 188 = 188 x 593
(By commutative law of multiplication)
(iv) 286 x 753 = 753 x 286
(By commutative law of multiplication)
(v) 38 x (91 x 37) = 91 x (38 x 37)
(By associative law of multiplication)
(vi) 13 x 100 x 1000 = 1300000
(vii) 59 x 66 + 59 x 34 = 59 x (66 + 34)
(By distributive law of multiplication)
(vii) 68 x 95 = 68 x 100 – 68 x 5
Question 2.
Solution:
(i) Commutative law of multiplication
(ii) Closure property
(iii) Associative law of multiplication
(iv) Multiplicative property of 1
(v) Multiplicative property of 0
(vi) Distributive law of multiplication over addition in whole numbers
(vii) Distributive law of multiplication over subtraction in whole numbers
Question 3.
Solution:
Using the law of distribution over addition and subtraction
(i) 647 x 13 + 647 x 7
= 647 x (13 + 7)
= 647 x 20
= 12940
(ii) 8759 x 94 + 8759 x 6
= 8759 x (94 + 6)
= 8759 x 100
= 875900
(iii) 7459 x 999 + 7459
= 7459 x 999 + 7459 x 1
= 7459 x (999 + 1)
= 7459 x 1000
= 7459000
(iv) 9870 x 561 – 9870 x 461
= 9870 x (561 – 461)
= 9870 x 100
= 987000
(v) 569 x 17 + 569 x 13 + 569 x 70
= 569 x (17 + 13 + 70)
= 569 x 100
= 56900
(vi) 16825 x 16825 – 16825 x 6825
= 16825 x (16825 – 6825)
= 16825 x 10000
= 168250000
= 472 x 1100 – 472 x 3
= 519200 – 1416
= 517784
(vi) 580 x 64
= 580 x (60 + 4)
= 580 x 60 + 580 x 4
= 34800 + 2320
= 37120
(