Question

Q1.5x -6y +30=0 (I)
5x +4y -20=0 (II)

SUBSITUTION METHOD!! HELP​

Answer 1

Explanation:

How to solve

step 1:From the given two Equations convert any two of the Equation into x or y form.

Step 2:Now,put x or y from step 1 into another equation to find another Variable's value.

Step 3:From step 2 again put this value into step 1.

➙5x-6y+30=0-----(1)

From equation 1

x=( -30 +6y)÷5----(2)

➙5x+4y-20=0-----(3)

From equation 2

put Equation 2 into Equation 3

➙5(-30+6y)÷5+4y= 20

➙-150+30y/5+4y= 20

➙-150+30y+20y/5=20

➙-150+50y/5=20

➙-150+50y=100

➙50y=100+150

➙50y= 250

➙y= 250÷50=25/5=5

y=5

Put y's value into equation 2

➙x=(-30+6y)÷5

➙x= -30+6(5)÷5

➙x= -30+30÷5

➙x=0÷5

➙x=0

x=0

Check:

➙5x-6y=-30

Taking LHS

➙5(0)-6(5)

➙0-30= -30

Since, LHS =RHS(Verified)