Question

Q1 = 6.0 nC is at (0.30 m, 0), Q2 = -1.0 nC is at (0, 0.10 m), Q3 = 5.0 nC is at (0, 0). What is the magnitude of the net force on the 5.0 nC charge? !!​

Answer 1

Answer:

Given, the charges, q1 = 5.00 nC, q2 = -3.00 nC and q3 = 6.00 nC seperation between, q1 and q2, r1 = 0.10 m seperation between, q1 and q3, r2= 0.30 m (a) Electric field at the origin due to q2 and q3 : Electric field at origin due to q2 : E2 = k*q2/ r12 = 9* 109 * -3.0* 10−9 / 0.12 = -2700C Electric field at origin due to q3: E3= k*q3/ r22 =9* 109 * 6.0* 10−9 / 0.32 = 600 C Net electric field, E =...