Question

Q1 =6 micro columb,Q2 = -3micro columb, r=10c.m,force=?​

Answer 1

electrostatic force

$f = k \frac{q1 \times q2}{r {}^{2} }$

where k is constant which value is 9×10^9

$9 \times 10 {}^{9 } \times \frac{6 \times 10 {}^{6} \times 3 \times 10 {}^{6} }{.1 {}^{2} } \\ = 162 \times 10 {}^{21 } \times 10 {}^{2} n \\ = 162 \times 10 {}^{21} n$

hope u got it