Q1. 9a²-1
Q2. a³ - 27
Q3. a³ + 125b³
Q4. 27a²+ 343
Q5. 16a⁴+54a
Q6. x²+5x +6
Q7. 2x²+7x+6
Q8. 12x²-7x+1
Q9. (2x+3y)²
Q10. (3a-5b)²
(Algebra)
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theta = 17/8. Csc theta = 1/ sin theta
This gives sin theta = 1/csc theta= 1/(17/8)=8/17
In trigonometry, sin theta=opposite side/hypotenuse.
By the Pythagorean theorem, a^2+b^2=c^2, where a and b are sides and c is the hypotenuse.
Letting a=8 and c=17, we have b^2=c^2-a^2
b^2=(17)^2-(8)^2
b^2=289–64=225; b=15
This is the adjacent side to theta, giving cos theta=15/17
Since tan theta = sin theta/cos theta , tan theta = (8/17)/(15/17)=8/15
cot theta = 1/tan theta = 1/(8/15)= 15/8. ANS.
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