Question

Q1. (a) A constant force of friction of 50 N is acting on a body of mass 200 kg moving initially with a speed
m/s. How long does the body take to stop? What distance will it cover before coming to rest?​

Answer 1

Answer:

Retarding force,

F = –50 N

Mass of the body,

m = 200 kg

Initial velocity of the body,

u = 15 m/s

Final velocity of the body,

v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

=> –50 = 200 × a

=> a= -50/200 = -0.25 m/s^2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

=> t= -u/a = -15/-0.25= 60 sec.

Explanation:

I hope it may help you

Answer 2

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