Question

Q1.A ball of mass 100 g strikes a wall normally with a
speed of 10 m/s and rebounds with the same speed
but in opposite direction. The magnitude of change
in linear momentum of the ball will be
​

Answer 1

Step-by-step explanation:

Answer:

The change in linear momentum is 2 kg/ms.

Explanation:

• Mass of the ball = 100 g
• Strikes the wall at speed of = 10 m/s
• The ball reverts back with the speed of = -10 m/s (as it is in opposite direction)

★ Change in momentum = Final momentum – Initial momentum

Initial momentum =

• m = 100 g = 0.1 kg
• u = 10 m/s
• v = -10 m/s

⟶ p = m × u

⟶ p = 0.1 × 10

⟶ p = 1 kg/ms

Final momentum =

⟶ p = m × v

⟶ p = 0.1 × -10

⟶ p = -1 kg/ms

★ Change in momentum =

⟶ Final momentum - Initial momentum

⟶ -1 - 1

⟶ -2 kg/ms

Change in momentum is of -2 kg/ms. Negative sign states that the change in momentum is in opposite direction of initial momentum.

Therefore, the change in linear momentum is 2 kg/ms.