Question

Q1.A bike starting from rest on a lake accelerates in a straight line at a constant rate of 3 metre per second square for 5 s. How far does the bike travel during this time?​

Answer 1

Explanation:

✬ Distance = 37.5 m ✬

Explanation:

Given:

• Initial velocity of bike 0 m/s.( started from rest )
• Acceleration produced by bike is 3 m/s².
• Time is 5 seconds.

To Find:

• Distance travelled by bike ?

Formula to be used:

s = ut + 1/2at²

Solution: Here we have

u = 0 m/s

s = ?

t = 5 seconds

a = 3 m/s²

Put the values on formula

⟹ s = ut + 1/2at²

⟹ s = 0(5) + 1/2(3)(5)²

⟹ s = 0 + 3/2 \times× 25

⟹ s = 0 + 75/2

⟹ s = 37.5

Hence, bike travelled 37.5 m during this time.