Question

Q1. A block weighing 1.0 kg is in the shape of a
cube of length 10 cm. It is kept on a horizontal table. Find the pressure on
the portion of the table where the block is kept. 

Answer 1

pressure = force / area
area of one side of cube =a×a=10×10=100 cm²
p=weight/area
p=1000/100
p=10
note:weight is also a force.
 

Answer 2

mass of block = 1 kg
weight = mg = 1×10 = 10N
area of base = 10×10 = 100cm² = 0.01 m²

pressure = force/area
so the pressure on the portion of the table where the block is kept is

p = $\frac{weight}{area} = \frac{10N}{0.01m^{2} } =1000$ N/m² = 1000 Pa