Question

Q1 A body is moving with a velocity of 54km/h. Thena force was applied and it started accelerating and its velocity became 108km/h in 3sec.If the mass of the body is 500kg, the value of force will be??​

Answer 1

Answer:

Force is 2500 N.

Explanation:

To find :

• Force.

Given that,

• Initial velocity, u is 54 km/h.
• Final velocity, v is 108 km/h.
• Time, t is 3 sec.
• Mass of body, m is 500 kg.

Conversion :

• u = 54 km/h = (54 × 5)/18 = 15 m/s .

• v = 108 km/h = (108 × 5)/18 = 30 m/s .

We know,

• Acceleration (a) = v-u/t

Put all values :

$\longrightarrow$ a = 30-15/3

$\longrightarrow$ a = 15/3

$\longrightarrow$ a = 5

Acceleration (a) is 5 m/s².

Now,

We also know that,

• Force (F) = ma

Put all values :

$\longrightarrow$ F = 500 × 5

$\longrightarrow$ F = 2500

Thus,

Force is 2500 Newton.

Answer 2

Answer:

❏ Given :

• Initial velocity, u is 54km/h
• Its velocity became 108km/h
• Time , T is 3 second
• Mass of the body is 500 kg

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❏ To find :

• Force

❏ Let's find :

• u = 54 km\h

${\large{\longrightarrow{\bf{ {\cancel\frac{54 \times 5}{18} = 15m \s }}}}}$

• v = 108 km\h

${\large{\longrightarrow{\bf{ {\cancel\frac{108 \times 5}{18} = 30 m\s}}}}}$

• Acceleration (a) = v-u/t

${\large{\longrightarrow{\bf{ {\frac{30 -15}{3} }}}}}$

${\large{\longrightarrow{\bf{ {\frac{15}{3} }}}}}$

$\sf\red{ = a = 5}$

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Acceleration (a) is 5m/s².

Now,

• Force (F) ma

⟶ F = 500 × 3

⟶ F = 2500

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❏ Hence,

• The value of force is 2500.