Question

Q1.a body moving along straight line such that its velocity represented through X and velocity gradient is represented through y then relation between X and y for moment under constant acceleration may be​

Answer 1

Explanation:

Given:

A body moving along straight line such that its velocity represented through X and velocity gradient is represented through Y.

To find:

Relation between X and Y for constant acceleration?

Calculation:

As per question:

v = X

dv/ds = gradient = Y

Let acceleration be constant and equal to k:

\therefore \: a = k∴a=k

$\implies \: \dfrac{dv}{dt} = k</p><p>$

Now, applying Chain Rule of Differentiation:

$\implies \: \dfrac{dv}{ds} \times \dfrac{ds}{dt} = k </p><p>$

$\implies \: \dfrac{dv}{ds} \times v = k </p><p>$

$\implies \: Y\times X = k$

$XY = k$

So, final answer is:

$\boxed{\bf XY = k} </p><p></p><p>$