Q1) A body of mass 80kg is moving with 10m/s collides with another body of mass 60kg moving with 20m/s. If after collision they entangle and continue to move. Determine their velocity after collision.
Answers
Answered by
3
As the linear momentum is always conserved.
m₁u₁ +m₂u₂ =( m₁+m₂)v
⇒80×10 +60×20 = (80+60)v
⇒140v = 2000
⇒v = 14.3 m/s
m₁u₁ +m₂u₂ =( m₁+m₂)v
⇒80×10 +60×20 = (80+60)v
⇒140v = 2000
⇒v = 14.3 m/s
Answered by
87
Answer:
Explanation:
Given :-
m₁ = 80 kg
u₁ = 10 m/s
m₂ = 60 kg
u₂ = 20 m/s
To Find :-
Velocity after collision.
Formula to be used :-
m₁u₁ +m₂u₂ =( m₁+m₂)v
Solution :-
Putting all the values, we get
m₁u₁ + m₂u₂ =( m₁ + m₂)v
⇒ 80×10 + 60 × 20 = (80 + 60)v
⇒ 140v = 2000
⇒ v = 14.3 m/s
Hence, velocity after collision is 14.3 m/s.
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