Physics, asked by itzpappu, 1 month ago

Q1.A car starts from rest and attains a velocity of 10 metre per second in 40

seconds .the driver applies brakes and slows down the car to 5 metre per

second in 10 seconds. Find the acceleration of the car in both the cases?​

Answers

Answered by oObrainlyreporterOo
5

Explanation:

✬ Acceleration = 0.25 & 0.5 m/s² ✬

Explanation:

Given: (Solving first case)

A car starts from rest.

Final velocity of car is 10 m/s.

Time taken to attain final velocity is 40 s.

To Find:

Acceleration of the car ?

Formula to be used:

V = u + at

Solution: Here we have

u = 0

v = 10 m/s

t = 40 s

a = ?

Substituting the values on formula

⟹ 10 = 0 + a × 40

⟹ 10 = 40a

⟹ 10/40 = a

⟹ 1/4 = a

⟹ 0.25 m/s² = a

So acceleration of car in first case is 0.25 m/s².

Given: (Second case)

Final velocity is 5 m/s.

Initial velocity is 10 m/s.

Time given is 10 s.

To Find:

Acceleration of the car ?

Formula to be used:

a = v – u/t

Solution: Here we have

u = 10 m/s

v = 5 m/s

t = 10 s

a = ?

Substituting the values on formula

⟹ a = 5 – 10/10

⟹ a = –5/10

⟹ a = –1/2

⟹ a = –0.5 m/s²

So, acceleration of car in second case is –0.5 m/s².

(You can also solve this one by using Newton's first law of motion , used in above case)

___________________

  • The velocity at which motion starts is termed as initial velocity. It is denoted by u.
  • The last velocity of an object after a period of time. It is denoted by v.
  • v = ut + 1/2at² ( Second law of motion)
  • v² = u² + 2as ( Third law of motion )
Answered by XxBRANDEDGIRLxX
2

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