Q1.A dealer buys an article marked at Rs. 25000 on two successive discounts
of first 20% and then 5%. He spends Rs. 1000 for its repair and then sells
t for Rs. 25000. What is his gain or loss percent?
Answers
Step-by-step explanation:
Solution
Given :-
dealer buys an article marked at = Rs. 25000
two successive discounts of first 20% and then 5%.
He spends Rs. 1000 for its repair .
S.P. of articles = Rs. 25000
Find :-
Gain or loss in percentage .
Explanation:-
First Calculate C.P. of this articles,
Case 1.
20% & 5% successive discount of in articles
so,
==> C.P. of articles = (80% × 95% × 25,000) + 1000
==> C.P. of articles = ( 80/100 × 95/100 × 25,000) + 1000
==> C.P. of articles = ( 8 × 95 × 25 ) + 1000
==> C.P. of articles = 8 × 2375 + 1000
==> C.P. of articles = 19,000 + 1000
==> C.P. of articles = 20,000
Here, S.P. is more than C.P.
Here, S.P. is more than C.P.since, Dealer got profit in this article
Now, Calculate Profit
==> Profit = 25,000 - 20,000
==> Profit = 5,000
Now, Calculate %profit
==> %profit = 5000 × 100/20,000
==> % profit = 50/2
==> %profit = 25%
Hence
%profit will be of an article = 25%
_______________
Answer:
25000 with a discount of 20% is 25000−20100×25000=20000. ... 20000 with a discount of 5% is 20000−5100×20000=19000. Then, he had to spend Rs. 1000 for its repairs and amends.
Step-by-step explanation:
:)