Question

Q1. A log of wood has area 20 cm 2 at one end and 1100cm 2 at the other end. A
force of 11000 N is applied on the first end. Calculate the pressure acting on it if
the broader end is used to hit the wall.

Answer 1

Answer:

$1m {}^{2} = 10000 \: cm {}^{2}$

$1100 \: cm {}^{2} = 0.11 \: m {}^{2}$

$pressure = \frac{force}{area}$

$\frac{11000 \times 100}{0.11 \times 100} = \frac{1100000}{11}$

Pressure = 1,00,000 Pa.

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